Q1
(a)
x1=5sin(2π208t)+sin(2π572t)+10sin(2π780t)GCD(208,572,780)=52Tx1=fx11=521sx2=20sin(2π392t)+5sin(2π784t)+30sin(2π1078t)GCD(208,572,780)=98Tx2=fx21=981s
(b)
No, they have different fundamental frequencies, so their pitch would be different.
Q2
(a)
s(t)= 7sin(2π10000t)+4sin(2π15000t)+5sin(2π20000t)+3sin(2π30000t)+2sin(2π35000t)
(b)
GCD(10000,15000,20000,30000,35000)=5000fs(t)=5000Hz
(c)
The 3rd and 4th harmonics.
(d)
Band-pass filter.
(e)
At 15000Hz, the filter’s amplitude is 1.
At 20000Hz, the filter’s amplitude is 0.5.

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Q3
(a)
The fundamental frequency of the signal is h=4sin(2π1.25t)

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(b)
The entire signal is h=4sin(2π1.25t)+3sin(2π2.5t)+2sin(2π3.75t)+2sin(2π5t)
